令x/(x+1)=t,則方程變?yōu)?br/>t -2/t=1
t²-t-2=0
(t-2)(t+1)=0
t=2或t=-1
x/(x+1)=2
x=2x+2
x=-2
x/(x+1)=-1
x=-x-1
2x=-1
x=-1/2
x=-2 x=-1/2,代入分式方程檢驗(yàn),分母均不等于0,兩個(gè)解都是分式方程的解.
x=-2 x=-1/2