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  • 因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1

    因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1
    數(shù)學(xué)人氣:113 ℃時(shí)間:2020-04-09 20:16:41
    優(yōu)質(zhì)解答
    x^5n+x^n+1
    =x^5n+x^4n+x^3n-x^4n-x^3n-x^2n+x^2n+x^n+1
    =x^3n(x^2n+x^n+1)-x^2n(x^2n+x^n+1)+(x^2n+x^n+1)
    =(x^2n+x^n+1)(x^3n-x^2n+1)
    2a^2-a^2b+(b-2)(ab-a)^2
    =(b-2)(ab-a)^2-a^2b+2a^2
    =(b-2)(ab-a)^2-a^2(b-2)
    =(b-2)[(ab-a)^2-a^2]
    =(b-2)(ab-a+a)(ab-a-a)
    =(b-2)(ab)(ab-2a)
    =a(b-2)(ab)(b-2)
    =ba^2*(b-2)^2
    x5+x4+x3+x2+x+1
    =(x5+x4)+(x3+x2)+(x+1)
    =x^4(x+1)+x^2(x+1)+(x+1)
    =(x+1)(x^4+x^2+1)
    x^4+y^4-2x^2y^2-2x^2-2y^2+1
    =x^4-2x^2y^2+y^4-2x^2-2y^2+1
    =(x^2-y^2)^2-2(x^2-y^2)+1
    =(x^2-y^2-1)^2
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