如圖,在直角梯形ABCD中,AB∥DC,∠ABC=90°,AB=2DC,對角線AC⊥BD,垂足為F,過點(diǎn)F作EF∥AB,交AD于點(diǎn)E,CF=4cm. (1)求證:四邊形ABFE是等腰梯形; (2)求AE的長.
如圖,在直角梯形ABCD中,AB∥DC,∠ABC=90°,AB=2DC,對角線AC⊥BD,垂足為F,過點(diǎn)F作
EF∥AB,交AD于點(diǎn)E,CF=4cm.
(1)求證:四邊形ABFE是等腰梯形;
(2)求AE的長.
![](http://hiphotos.baidu.com/zhidao/pic/item/0eb30f2442a7d933361939f0ae4bd11372f00184.jpg)
(1)求證:四邊形ABFE是等腰梯形;
(2)求AE的長.
數(shù)學(xué)人氣:896 ℃時間:2019-08-17 13:26:12
優(yōu)質(zhì)解答
(1)證明:過點(diǎn)D作DM⊥AB,∵DC∥AB,∠CBA=90°,∴四邊形BCDM為矩形.∴DC=MB.∵AB=2DC,∴AM=MB=DC.∵DM⊥AB,∴AD=BD.∴∠DAB=∠DBA.∵EF∥AB,AE與BF交于點(diǎn)D,即AE與FB不平行,∴四邊形ABFE是等腰梯形.(...
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