已知等差數(shù)列{An}的前N項(xiàng)和為Sn 且S4/S8=1/3 則S8/S16=?A 3/10 B 1/3 C 1/9 D 1/8
已知等差數(shù)列{An}的前N項(xiàng)和為Sn 且S4/S8=1/3 則S8/S16=?A 3/10 B 1/3 C 1/9 D 1/8
不用公式進(jìn)行計(jì)算,因?yàn)榈炔顢?shù)列有個(gè)規(guī)律:Sn,S2n-Sn,S3n-S2n。是等差數(shù)列
不用公式進(jìn)行計(jì)算,因?yàn)榈炔顢?shù)列有個(gè)規(guī)律:Sn,S2n-Sn,S3n-S2n。是等差數(shù)列
數(shù)學(xué)人氣:798 ℃時(shí)間:2020-05-24 04:45:10
優(yōu)質(zhì)解答
因?yàn)榈炔顢?shù)列有個(gè)規(guī)律:Sn,S2n-Sn,S3n-S2n……是等差數(shù)列,所以S4、S8-S4、S12-S8、S16-S12是等差數(shù)列故2(S8-S4)=S4+(S12-S8),即S12=3(S8-S4);2(S12-S8)=(S8-S4)+(S16-S12),即S16=3(S12-S8)+S4又S4/S8=1/3,故S8=3S4...S12=3(S8-S4);?????移項(xiàng)合并同類項(xiàng)即得
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