(2011?武漢模擬)已知?jiǎng)狱c(diǎn)M(x、y)到點(diǎn)F(4,0)的距離比到直線x+5=0的距離小1,則點(diǎn)M的軌跡方程為( ?。?br/>A. x+4=0
B. x-4=0
C. y2=8x
D. y2=16x
∵動(dòng)點(diǎn)M(x、y)到點(diǎn)F(4,0)的距離比到直線x+5=0的距離小1,
∴點(diǎn)M(x、y)到點(diǎn)F(4,0)的距離和到直線x+4=0的距離相等,
點(diǎn)M的軌跡是以點(diǎn)F為焦點(diǎn),直線x+4=0為準(zhǔn)線的拋物線.
∴
=4,∴P=8,故拋物線方程為y
2=16x,
故選 D.