設(shè)函數(shù)f(x)=sin(2X+π/4)+cos(2X+π/4)的化簡
設(shè)函數(shù)f(x)=sin(2X+π/4)+cos(2X+π/4)的化簡
數(shù)學(xué)人氣：943 ℃時間：2020-03-16 22:21:21
優(yōu)質(zhì)解答
解法一：f(x)=sin(2X+π/4)+cos(2X+π/4)=√2[√2/2sin(2X+π/4)+√2/2cos(2X+π/4)]=√2sin(2x+π/4+π/4)=√2sin(2x+π/2)=√2cos2x.解法二：f(x)=sin(2X+π/4)+cos(2X+π/4)=√2/2sin2x+√2/2cos2x+√2/2cos2x-√...
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