f(x)=sinxcosx-(sinx+cosx)
=0.5[1-(sinx+cosx)]²-1
sinx+cosx=根號2sin(x+π/4)
函數(shù)f(x)在 (0,π/2)上的單調(diào)遞增區(qū)間是(π/4,π/2)若函數(shù)f(x)在區(qū)間(π/2,π)上是單調(diào)遞減函數(shù),求實數(shù)m的取值范圍
已知函數(shù)f(x)=sinxcosx-m(sinx+cosx),(1)若m=1,求函數(shù)f(x)在(0,π/2)上的單調(diào)增區(qū)間,(2)若函數(shù)f(x)
已知函數(shù)f(x)=sinxcosx-m(sinx+cosx),(1)若m=1,求函數(shù)f(x)在(0,π/2)上的單調(diào)增區(qū)間,(2)若函數(shù)f(x)
在區(qū)間(π/2,π)上市單調(diào)遞減函數(shù),求實數(shù)m的取值范圍
在區(qū)間(π/2,π)上市單調(diào)遞減函數(shù),求實數(shù)m的取值范圍
數(shù)學人氣:923 ℃時間:2020-06-16 01:21:51
優(yōu)質(zhì)解答
我來回答
類似推薦
- 已知函數(shù)f(x)=sinxcosx-m(sinx+cosx) (1)若m=1,求函數(shù)f(x)zai (0,π/2)上的單調(diào)遞增區(qū)間
- 求函數(shù)f(x)=sinx+cosx+sinxcosx.x∈(0,π3)的最大值并求出相應的x值.
- 函數(shù)f(x)=sinxcosx/(1+sinx+cosx)的值域
- f(x)=sinx^4+2倍根號3 sinxcosx-cosx^4 求(1)函數(shù)f(x)最小正周期 (2)函數(shù)在閉區(qū)間0到π閉區(qū)間上的單調(diào)
- 函數(shù)f(x)=(sinxcosx)/(1+sinx+cosx)的值域為___________
- 已知實數(shù)x,y滿足2x+3y≤14,2x+y≤9,x≥0,y≥0,S=3x+ay,若S取得最大值時的最優(yōu)解有無窮多個,則實數(shù)a=?
- 請問這種成分還屬301不銹鋼嗎?(C-0.1003;Si-0.2467;Mn-2.2387;p-0.358;S-0.169;Cr-14.6342;Ni-6.0215)
- X=2*3*5*7*11*13*17*19*23*29*.N(N為質(zhì)數(shù)),求證:X+1為質(zhì)數(shù)
- 若√2007n是個非零整數(shù),則最小整數(shù)n是?
- Either I or he ( )soccer with Tom 四個選項 play are plays is
- .the music festival was great!Many famous people (attended) it.
- 如果(M)表示m的全部因數(shù)的和,如(4)=1+2+4=7,則(18)-(21)=()