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  • 已知函數(shù)f(x)=sin^2ωx+√3 sinωxsin(ωx+π/2)(ω>0)的最小正周期為π

    已知函數(shù)f(x)=sin^2ωx+√3 sinωxsin(ωx+π/2)(ω>0)的最小正周期為π
    (1) 求f(x)
    (2) 當(dāng)x∈[-π/12,π/2]時(shí),求函數(shù)f(x)的值域
    數(shù)學(xué)人氣:349 ℃時(shí)間:2020-03-31 06:14:59
    優(yōu)質(zhì)解答
    (1)
    f(x) = sin²(ωx) + √3 sin(ωx)sin(ωx+π/2) = sin²(ωx) + √3sin(ωx)cos(ωx)
    = 2[(1/2)sin(ωx) + (√3/2)cos(ωx)]sin(ωx)
    = 2[cos(π/3)sin(ωx) + sin(π/3)cos(ωx)]sin(ωx)
    = 2sin(ωx + π/3)sin(ωx)
    = 2*(1/2)[cos(ωx + π/3 - ωx) - cos(ωx + π/3 + ωx)]
    = -cos(2ωx + π/3) + cos(π/3)
    = -cos(2ωx + π/3) + 1/2
    = cos(2ωx + π/3 - π) + 1/2
    = cos(2ωx - 2π/3) + 1/2
    最小正周期為π = 2π/(2ω),ω = 1
    f(x) = cos(2x - 2π/3) + 1/2
    (2)
    x∈[-π/12,π/2]:
    f(π/3) = cos(2π/3 - 2π/3) + 1/2 = 1 + 1/2 = 3/2,此為最大值
    x = π/3為f(x)最大值處的對(duì)稱(chēng)軸
    π/3 - (-π/12) = 5π/12
    π/2 - π/3 = 2π/12 < 5π/12
    x = -π/12比x = π/2與x = π/3對(duì)稱(chēng)軸更遠(yuǎn),最小值f(-π/12) = cos(-π/6 - 2π/3) + 1/2
    = (1 - √3)/2
    值域:[(1 - √3)/2,3/2]
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