設(shè)z1=x1+iy1
z2=x2+iy2
左邊=x1-iy1+x2-y2
z1+z2=x1+x2+iy1+iy2
其共軛=x1+x2-iy1-iy2
得證
求證：z1的共軛復(fù)數(shù)+z2的共軛復(fù)數(shù)=z1+z2的共軛復(fù)數(shù)
求證：z1的共軛復(fù)數(shù)+z2的共軛復(fù)數(shù)=z1+z2的共軛復(fù)數(shù)
數(shù)學(xué)人氣：492 ℃時間：2019-10-26 21:28:46
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