f(x)配方：f(x)=-[x-(t-1/2)]^2+t^2+1+(t-1/2)^2=-[x-(t-1/2)]^2+2t^2-t+5/4
最大值g(t)=2t^2-t+5/4對g(t)與方：g(t)=2(t-1/4)^2+5/4-1/8=2(t-1/4)^2+9/8即g(t)的最小值為9/8??????????????????????????????????????f??x????-x²????2t-1??x????t²??1??=-[x²-(2t-1)x]+(t²+1), ???????????????????????-1; =-[x²-(2t-1)x+(2t-1)²/4-(2t-1)²/4]+(t²+1); ?????????????=-[(x-(2t-1)/2)²-(2t-1)²/4]+(t²+1);?????????=-(x-(2t-1)/2)²+(2t-1)²/4+(t²+1),?????????=-(x-(2t-1)/2)²+2t²-t+5/4, ???