3 |
=
3 |
=2sin(2x+
π |
6 |
則y=f(x)的最小正周期為:π.
由2kπ-
π |
2 |
π |
6 |
π |
2 |
kπ-
π |
3 |
π |
6 |
∴y=f(x)的單調(diào)遞增區(qū)間為:[kπ-
π |
3 |
π |
6 |
(2)由x∈[-
5π |
12 |
π |
3 |
2π |
3 |
π |
6 |
5π |
6 |
考察函數(shù)y=sinx,易知?1≤sin(2x+
π |
6 |
于是?3≤2sin(2x+
π |
6 |
故y=f(x)的取值范圍為:[-3,1].
3 |
5π |
12 |
π |
3 |
3 |
3 |
π |
6 |
π |
2 |
π |
6 |
π |
2 |
π |
3 |
π |
6 |
π |
3 |
π |
6 |
5π |
12 |
π |
3 |
2π |
3 |
π |
6 |
5π |
6 |
π |
6 |
π |
6 |