原式=sin[π-(7π/8-x)]cos(x+π/8)
=sin(x+π/8)cos(x+π/8)
=1/2[2sin(x+π/8)cos(x+π/8)]
=1/2sin[2(x+π/8)]
=(1/2)sin(2x+π/4)
將函數(shù)y=sin(7π/8-x)cos(x+π/8)的化簡(jiǎn)
將函數(shù)y=sin(7π/8-x)cos(x+π/8)的化簡(jiǎn)
數(shù)學(xué)人氣:854 ℃時(shí)間:2020-05-13 03:04:52
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