(3-2x)/(x-3)+(2+mx)/(3-x)=-1,
(3-2x)/(x-3)-(2+mx)/(x-3)=-1,
兩邊同時(shí)乘以(x-3)(3-2x)-(2+mx)=-(x-3),
3-2x-2-mx=-x+3,
-x-mx=2,
-(1+m)x=2x=-2/(m+1),
分類討論,要使原方程無(wú)解,(1)x=3(x=3是方程的增根),得,
-(1+m)*3=2,
m=-5/3.,
(2)1+m=0,則x的值無(wú)意義,∴m=-1,
嘻嘻……綜上,當(dāng)m=-1和-5/3時(shí),原方程無(wú)解.