已知函數(shù)fx=x+m/x,且f1=2,gx為定義在R上的奇函數(shù),判斷Fx=fx×gx的奇偶性
已知函數(shù)fx=x+m/x,且f1=2,gx為定義在R上的奇函數(shù),判斷Fx=fx×gx的奇偶性
數(shù)學(xué)人氣:398 ℃時(shí)間:2019-11-04 15:00:45
優(yōu)質(zhì)解答
因f1=2 所以m=1 易知fx為奇函數(shù) 所以F(-x)=f(-x)Xg(-x)=f(x)X g(x)=F(x) 所以F(x)為偶函數(shù)
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