若等差數(shù)列5,4(2/7),3(4/7),…的前n項(xiàng)和為Sn 求使得Sn最大的項(xiàng)數(shù)n的值
若等差數(shù)列5,4(2/7),3(4/7),…的前n項(xiàng)和為Sn 求使得Sn最大的項(xiàng)數(shù)n的值
若等差數(shù)列5,4又7分之2,3又7分之4,…的前n項(xiàng)和為Sn,求使得Sn最大的項(xiàng)數(shù)n的值.
若等差數(shù)列5,4又7分之2,3又7分之4,…的前n項(xiàng)和為Sn,求使得Sn最大的項(xiàng)數(shù)n的值.
數(shù)學(xué)人氣:830 ℃時(shí)間:2020-08-27 08:17:42
優(yōu)質(zhì)解答
Sn=n/2(a1+an)因?yàn)閍n=a1+(n-1)d,所以,Sn=n/2(2a1+dn-d)=(75/14)n-(5/14)n^2現(xiàn)在當(dāng)做一個(gè)開(kāi)口向下的拋物線來(lái)求最大值時(shí)候的自變量的值,(過(guò)程不用多說(shuō)了吧),對(duì)稱軸=+7.5,因?yàn)閚是整數(shù),所以當(dāng)n為8或者6的時(shí)候sn有最大值
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