求dy/dx=x/y+(cosx/y)^2通解
求dy/dx=x/y+(cosx/y)^2通解
數(shù)學(xué)人氣：411 ℃時(shí)間：2020-05-12 11:30:18
優(yōu)質(zhì)解答
求dy/dx=(x/y)+cos²(x/y)通解令x/y=u,則y=x/u,dy/dx=[u-x(du/dx)]/u²,代入原式得：[u-x(du/dx)]/u²=u+cos²u=u+(1+cos2u)/2u-x(du/dx)=u³+u²(1+cos2u)/2u³-u+u²(1+cos2u)/2=...
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