已知:如圖,菱形ABCD中,E,F(xiàn)分別是CB,CD上的點(diǎn),且BE=DF. (1)求證:AE=AF; (2)若∠B=60°,點(diǎn)E,F(xiàn)分別為BC和CD的中點(diǎn),求證:△AEF為等邊三角形.
已知:如圖,菱形ABCD中,E,F(xiàn)分別是CB,CD上的點(diǎn),且BE=DF.
![](http://hiphotos.baidu.com/zhidao/pic/item/ac6eddc451da81cb341b7f7c5166d01608243185.jpg)
(1)求證:AE=AF;
(2)若∠B=60°,點(diǎn)E,F(xiàn)分別為BC和CD的中點(diǎn),求證:△AEF為等邊三角形.
![](http://hiphotos.baidu.com/zhidao/pic/item/ac6eddc451da81cb341b7f7c5166d01608243185.jpg)
(1)求證:AE=AF;
(2)若∠B=60°,點(diǎn)E,F(xiàn)分別為BC和CD的中點(diǎn),求證:△AEF為等邊三角形.
數(shù)學(xué)人氣:299 ℃時(shí)間:2020-03-29 20:26:06
優(yōu)質(zhì)解答
證明:(1)由菱形ABCD可知:AB=AD,∠B=∠D,∵BE=DF,∴△ABE≌△ADF(SAS),∴AE=AF;(4分)(2)連接AC,∵菱形ABCD,∠B=60°,∴△ABC為等邊三角形,∠BAD=120°,(2分)∵E是BC的中點(diǎn),∴AE⊥BC(等腰三角...
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