1 |
x |
自變量應(yīng)滿足x≠0
故f(x)的定義域為(-∞,0)∪(0,+∞)
由于
1 |
x |
1 |
x |
故f(x)的值域為(-∞,-2)∪(-2,+∞)
(2)任取區(qū)間(0,+∞)上兩個任意的實數(shù)x1,x2,且x1<x2,
則x1>0,x2>0,x2-x1>0,
則f(x1)-f(x2)=(
1 |
x1 |
1 |
x2 |
1 |
x1 |
1 |
x2 |
x2?x1 |
x1?x2 |
即f(x1)>f(x2)
故函數(shù)f(x)=
1 |
x |
1 |
x |
1 |
x |
1 |
x |
1 |
x |
1 |
x |
1 |
x1 |
1 |
x2 |
1 |
x1 |
1 |
x2 |
x2?x1 |
x1?x2 |
1 |
x |