函數(shù)y=sin(π3?1/2x),x∈[?2π,2π]的單調遞增區(qū)間為_.
函數(shù)y=sin(
?
x),x∈[?2π,2π]的單調遞增區(qū)間為______.
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數(shù)學人氣:263 ℃時間:2020-05-27 04:51:24
優(yōu)質解答
∵y=sin(π3-12x)=-sin(12x-π3),∴由2kπ+π2≤12x-π3≤3π2+2kπ(k∈Z)得:4kπ+5π3≤x≤11π3+4kπ(k∈Z),∴y=sin(π3-12x)的遞增區(qū)間為[4kπ+5π3,11π3+4kπ](k∈Z),又x∈[-2π,2π],∴y=s...
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