f(0) = d = -7
f'(x) = 3ax² + 2bx + c
f'(0) = c = -18
f'(-1) = 3a - 2b - 18 = 0
f'(3) = 27a + 6b -18 = 0
a = 2,b = -6
y = 2x³ - 6x² - 18x - 7
已知函數(shù)f(x)=ax^3+bx^2+cx+d的兩個(gè)極值點(diǎn)是-1和3,且f(0)=-7,f`(0)=-18,求f(x)的表達(dá)式
已知函數(shù)f(x)=ax^3+bx^2+cx+d的兩個(gè)極值點(diǎn)是-1和3,且f(0)=-7,f`(0)=-18,求f(x)的表達(dá)式
數(shù)學(xué)人氣：663 ℃時(shí)間：2019-09-17 17:09:33
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