![](http://a.hiphotos.baidu.com/zhidao/wh%3D600%2C800/sign=873ff0579e2f07085f502206d91494a1/0ff41bd5ad6eddc4513356e339dbb6fd536633d5.jpg)
設(shè)在a的某鄰域內(nèi)有f(x)有連續(xù)的二階導(dǎo)數(shù),且f'(a)不等于0,求w=(x->a)lim{[[1/f(x)-f(a)]-[1/(x-a)f'(a)]}
設(shè)在a的某鄰域內(nèi)有f(x)有連續(xù)的二階導(dǎo)數(shù),且f'(a)不等于0,求w=(x->a)lim{[[1/f(x)-f(a)]-[1/(x-a)f'(a)]}
設(shè)在a的某鄰域內(nèi)有f(x)有連續(xù)的二階導(dǎo)數(shù),且f'(a)不等于0,求
w=(x->a)lim{[[1/f(x)-f(a)]-[1/(x-a)f'(a)]}
我想了很久也不懂,想的痛苦了,
設(shè)在a的某鄰域內(nèi)有f(x)有連續(xù)的二階導(dǎo)數(shù),且f'(a)不等于0,求
w=(x->a)lim{[[1/f(x)-f(a)]-[1/(x-a)f'(a)]}
我想了很久也不懂,想的痛苦了,
數(shù)學(xué)人氣:537 ℃時(shí)間:2020-05-04 01:01:18
優(yōu)質(zhì)解答
我沒(méi)算錯(cuò)應(yīng)該是 - f''(a) / 2[f'(a)]^2
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