由f'(x)=x^2-3ax+2a^2=(x-2a)(x-a)=0,得x=a,2a
當(dāng)a>0時(shí),f(a)=a^3/3-3a^3/2+2a^3+a^3/6=a^3為極大值
f(2a)=a^3(8/3-6+4+1/6)=5/6*a^3為極小值
當(dāng)a=0時(shí),f'(x)=x^2>=0,f(x)沒有極值
當(dāng)a
已知a為實(shí)數(shù),函數(shù)f(x)=1/3x^3-3/2ax^2+2a^2x+1/6a^3,f·(x)是f(x)的導(dǎo)函數(shù),求f(x)的極值
已知a為實(shí)數(shù),函數(shù)f(x)=1/3x^3-3/2ax^2+2a^2x+1/6a^3,f·(x)是f(x)的導(dǎo)函數(shù),求f(x)的極值
數(shù)學(xué)人氣:367 ℃時(shí)間:2020-03-24 09:27:44
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