你好!
由題意
6cos²α + sin²α = 5
又 cos²α+sin²α =1
解得 cos²α = 4/5 sin²α = 1/5
cos(2α) = cos²α - sin²α = 3/5
(2)∵α是銳角
∴π/2 < 2α < π
sin(2α) >0
tan(2α) = sin(2α) / cos(2α)
= √(1 - cos²2α) / cos(2α)
= 4/3
tan(2α - π/4)
= [ tan(2α) - tan(π/4) ] / [ 1+ tan(2α) tan(π/4) ]
= (4/3 - 1) / (1 + 4/3 *1)
= 1/7
已知α為銳角,且點(diǎn)(cosα,sinα)在曲線6x^2+y^2=5上,(1)求cos2α(2)求tan(2α-π/4)的值
已知α為銳角,且點(diǎn)(cosα,sinα)在曲線6x^2+y^2=5上,(1)求cos2α(2)求tan(2α-π/4)的值
數(shù)學(xué)人氣:855 ℃時(shí)間:2020-05-01 04:03:37
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