已知圓c:(x-3)²+(y-4)²=16 (1)有動(dòng)點(diǎn)P引圓c的兩條切線(xiàn)PA、PB的斜率分別為k1、k2,
已知圓c:(x-3)²+(y-4)²=16 (1)有動(dòng)點(diǎn)P引圓c的兩條切線(xiàn)PA、PB的斜率分別為k1、k2,
且滿(mǎn)足k1+k2+k1·k2=-1,求動(dòng)點(diǎn)P的軌跡方程
且滿(mǎn)足k1+k2+k1·k2=-1,求動(dòng)點(diǎn)P的軌跡方程
數(shù)學(xué)人氣:329 ℃時(shí)間:2019-08-26 05:38:29
優(yōu)質(zhì)解答
由動(dòng)點(diǎn)P引圓x平方+y平方=10的兩條切線(xiàn)PA,PB,直線(xiàn)PA,PB的斜率分別為k1,k2 (1)若k1+k2+k1×k2=-1,求動(dòng)點(diǎn)P的軌跡方程(2)若點(diǎn)P在直線(xiàn)x+y=m上,且PA⊥PB,求實(shí)數(shù)m的取值范圍 1) 若k1+k2+k1×k2=-1,求動(dòng)點(diǎn)P的軌跡方程設(shè)...
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