（1）設(shè)向量OZ=(x,y),則ZA=(1-x,7-y), ZB=(5-x,1-y)
又點(diǎn)Z在直線OP上,∴有 k(OZ)=y/x=1/2=k(OP)
∴向量ZA.向量ZB=(1-x)(5-x)+(7-y)(1-y)
=5-6x+x^2+7-8y+y^2
=5-12y+4y^2+7-8y+y^2
=12-20y+5y^2
=5(y-2)^2-8
≥-8
當(dāng)且僅當(dāng)y=2時(shí),x=4時(shí),取得最小值-8
∴此時(shí)向量OZ=(4,2)
（2）∵向量ZA.向量ZB=|ZA|*|ZB|*cos∠AZB
∴cos∠AZB=向量ZA.向量ZB/(|ZA|*|ZB|)
而|ZA|=|(1-4,7-2)|=√34,|ZB|=|(5-4,1-2)|=√2,
向量ZA.向量ZB最小值=-8
∴cos∠AZB=-8/(√34*√2)=-4/√17