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  • A,B是拋物線y^2=2px(p>0)上的兩點(diǎn),滿(mǎn)足OA垂直O(jiān)B,求證直線AB恒過(guò)一定點(diǎn)

    A,B是拋物線y^2=2px(p>0)上的兩點(diǎn),滿(mǎn)足OA垂直O(jiān)B,求證直線AB恒過(guò)一定點(diǎn)
    這個(gè)答案最后一步怎么得到的不理解啊
    (y1+y2)*y=2p(x-2p)怎么求?
    (y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?(y1+y2)*y=2p(x-2p)怎么求?
    數(shù)學(xué)人氣:273 ℃時(shí)間:2019-10-17 00:37:11
    優(yōu)質(zhì)解答
    設(shè)A(X1,Y1),B(X2,Y2)則 y1^2=2px1,y2^2=2px2
    ∠AOB=90
    (y1*y2)/(x1*x2)=-1 即y1*y2=-4P^2
    由直線AB得:y-y1=(y1-y2)/(x1-x2)*(x-x1)
    因?yàn)?y1^2=2px1,y2^2=2px2兩式相減
    y1^2-y^2=2p(x1-x2)
    (y1+y2)(y1-y2)=2p(x1-x2)
    (y1-y2)/(x1-x2)=2p/(y1+y2)
    故y-y1=2p/(y1+y2)*(x-x1)
    又y1*y2=-4P^2,y1^2=2px1,y2^2=2px2
    (y-y1)(y1+y2)=2p*(x-x1)
    yy1+yy2-y1^2-y1y2=2px-2px1
    yy1+yy2-2px1+4p^2=2px-2px1
    yy1+yy2=2px-4p^2
    故(y2+y1)*y=2p*(x-2p)
    x=2p時(shí),y恒為0
    所以直線AB過(guò)定點(diǎn)(2p,0)
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