令-π/2+2kπ≤2x+π/6≤π/2+2kπ解得 -π/3+kπ≤x≤π/6+kπ即y的增函數(shù)區(qū)間為[ -π/3+kπ,π/6+kπ]同理得減區(qū)間為[ π/6+kπ,2π/3+kπ],k∈Z所以y在[0,π/6]上增,在[π/6,π/2]上減,所以,當(dāng)x=π/6時(shí),sin(2x+π...