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  • 數(shù)列Cn=n(1/2)^n,求前n項(xiàng)和Sn.

    數(shù)列Cn=n(1/2)^n,求前n項(xiàng)和Sn.
    數(shù)學(xué)人氣:716 ℃時(shí)間:2020-05-17 18:15:43
    優(yōu)質(zhì)解答
    Sn=1*(1/2)+2*(1/2)^2+3*(1/2)^3+-----+(n-1)*(1/2)^(n-1)+n*(1/2)^n;
    Sn/2=1*(1/2)^2+2*(1/2)^3+3*(1/2)^4+-----+(n-1)*(1/2)^n+n*(1/2)^(n+1);
    Sn-Sn/2=1*(1/2)+(2-1)*(1/2)^2+(3-2)*(1/2)^3+-----+(n-n+1)*(1/2)^n-n*(1/2)^(n+1)
    = Sn/2 =(1/2)+(1/2)^2+(1/2)^3+-----+(1/2)^n-n*(1/2)^(n+1)
    =(1/2)(1-(1/2)^n)/(1-(1/2))-n*(1/2)^(n+1)=1-(1/2)^n-n*(1/2)^(n+1)
    =1-(n+2)*(1/2)^(n+1)
    Sn=2-(n+2)/2^n
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